J-9 
ANSWERS to the SAMPLE LABORATORY EXAMINATION 
 
MULTIPLE CHOICE 
 
 
1. 
a. 
Cu(NO3)2 
(aq)
  +  Na2CO3 
(aq)  
?  CuCO3 
(s)
  +  2 NaNO3 
(aq) 
2.  
c. 
143 mL 
3. 
d. 
CoCl2
6 H2O 
4. 
b. 
696.1 
5.  
a. 
NaOH 
6. 
d. 
Q > K, reaction is moving to the left 
7.  
a. 
0.03922 M 
8. 
e. 
more than 0.5080 M 
9. 
c. 
methyl red 
10. 
d. 
1.824 g 
11. 
d. 
½ the volume to the equivalence point 
12. 
d. 
3.69 
 
 
SHORT ANSWER 
 
13. 
a.  BaCl2 
 
b.  13.6% 
 
c.  BaCl2
2H2O  
 
14. 
mass NaNO2 = 0.333 g; 
mass HSO3NH2 = 0.468 g; 
V = 129 mL  (P
N2
 = 0.906 atm) 
 
15.  
a. 
Cd
2+
(aq)
 + C2O
4
2-
(aq)  
  CdC2O
4(s) 
   
or  
CdC2O
4(s)
?  
  ?Cd
2+
(aq)
 + C2O
4
2-
(aq)  
 
 
b. 
#1  
Control - essentially no effect due to the low solubility of CdC2O
4(s) 
 
 
 
#2  
HCl addition - two interactive equilibria occur 
 
 
 
i)   
Cd
2+
(aq)
 + Cl
-
(aq)  
  [CdCl]
+
(aq)  
 
 
 
ii)   
C2O
4
2-
(aq)
 + 2 H3O
+
(aq)   
  H2C2O
4(aq)
 
+ 2 H2O
(l) 
 
 
 
#3  
HNO3 addition - only one interactive equilibria occurs 
 
 
 
i)   
C2O
4
2-
(aq)
 + 2 H3O
+
(aq)   
  H2C2O
4(aq)
 
+ 2 H2O
(l) 
 
 
There is less solid CdC2O
4
 remaining in test tube #2 because the concentrations of both the Cd
2+
(aq)
 and 
C2O
4
2-
(aq) 
are decreased by the addition of the HCl.  Therefore, more CdC2O
4(s) 
must dissolve to 
reestablish equilibrium, compared to test tube #3, where only the Cd
2+
(aq)
 reacts with the HNO3 added 
(NO3
-
(aq)
 does not react). 
 
16. 
a. 
[I3
-
] = 1.18 x 10
-2 
M 
b.  [I
-
] = 0.0882 M  
c.  637  
 
17. 
a. 
[CH3COOH] = 0.2151 M 
b.  K
+
 and CH3COO
-
  and OH
- 
 
c. 
[CH3COO
-
] = 0.1065 M 
d. 
0.70 % 
 
e. 
8.891 
 
 
BONUS QUESTION 
 
18.  
34 mL