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J-9
ANSWERS to the SAMPLE LABORATORY EXAMINATION
MULTIPLE CHOICE
1.
a.
Cu(NO3)2
(aq)
  +  Na2CO3
(aq) 
?  CuCO3
(s)
  +  2 NaNO3
(aq)
2. 
c.
143 mL
3.
d.
CoCl2
6 H2O
4.
b.
696.1
5. 
a.
NaOH
6.
d.
Q > K, reaction is moving to the left
7. 
a.
0.03922 M
8.
e.
more than 0.5080 M
9.
c.
methyl red
10.
d.
1.824 g
11.
d.
½ the volume to the equivalence point
12.
d.
3.69
SHORT ANSWER
13.
a.  BaCl2
b.  13.6%
c.  BaCl2
2H2
14.
mass NaNO2 = 0.333 g;
mass HSO3NH2 = 0.468 g;
V = 129 mL  (P
N2
= 0.906 atm)
15. 
a.
Cd
2+
(aq)
+ C2O
4
2-
(aq) 
  CdC2O
4(s)
 
or
CdC2O
4(s)
  ?Cd
2+
(aq)
+ C2O
4
2-
(aq)
b.
#1 
Control - essentially no effect due to the low solubility of CdC2O
4(s)
#2 
HCl addition - two interactive equilibria occur
i)  
Cd
2+
(aq)
+ Cl
-
(aq) 
  [CdCl]
+
(aq)
ii)  
C2O
4
2-
(aq)
+ 2 H3O
+
(aq)  
  H2C2O
4(aq)
+ 2 H2O
(l)
#3 
HNO3 addition - only one interactive equilibria occurs
i)  
C2O
4
2-
(aq)
+ 2 H3O
+
(aq)  
  H2C2O
4(aq)
+ 2 H2O
(l)
There is less solid CdC2O
4
remaining in test tube #2 because the concentrations of both the Cd
2+
(aq)
and
C2O
4
2-
(aq)
are decreased by the addition of the HCl.  Therefore, more CdC2O
4(s)
must dissolve to
reestablish equilibrium, compared to test tube #3, where only the Cd
2+
(aq)
reacts with the HNO3 added
(NO3
-
(aq)
does not react).
16.
a.
[I3
-
] = 1.18 x 10
-2
M
b.  [I
-
] = 0.0882 M 
c.  637
17.
a.
[CH3COOH] = 0.2151 M
b.  K
+
and CH3COO
-
  and OH
-
c.
[CH3COO
-
] = 0.1065 M
d.
0.70 %
e.
8.891
BONUS QUESTION
18. 
34 mL
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