Practice term test #2
- [5] When heated, diaminoselenium, (NH2)2Se,
decomposes according to the equation
(NH2)2Se(s)
--> 1/8Se8(s) + N2(g)
+ 2H2(g)
A sample of solid diaminoselenium, (NH2)2Se(s),
was placed in an evacuated cylinder and heated to 300 degrees C, resulting
in the formation of a mixture of molecular nitrogen, elemental selenium
and molecular hydrogen gas. After twenty minutes of heating at 300 degrees
C, the reaction reached equilibrium and the total pressure climbed to
a maximum value of 8.44 atmospheres. Some solid diaminoselenium was still
present in the cylinder at equilibrium. Use the information given to calculate
Kp for the diaminoselenium decomposition reaction at 300 degrees
C.
p(total)
= 8.44 atm = p(N2) + p(H2)
Let
x = p(N2). Then, from the balanced reaction, since two
moles of H2 form for every mole of N2 (which means that p(H2)
= 2p(N2) ), it must be that
i) p(N2) = x (already said this!)
ii) p(H2) = 2x
iii) since p(total) = p(H2) + p(N2), then p(total)
= 3x
p(total)
= 8.44 atm = p(N2) + p(H2)
= 3x
x
= 2.813 atm
Kp
=4 * (2.813)3 = 89.0
- [6] At elevated temperatures, potassium perchlorate
decomposes to produce potassium hypochlorite and molecular oxygen gas.
A 0.8988 g sample of impure potassium perchlorate was heated until
the production of molecular oxygen gas ceased. A total 48.8 mL of molecular
oxygen gas were collected in a buret over water at a temperature of
22.0 oC and a barometric pressure of 734 mm Hg. A water column
2.23 cm high was observed inside the buret.
a)
Write a balanced equation for the decomposition reaction.
KClO4 (s) --> KClO
(s) + 3/2 O2 (g)
b)
Calculate the mass percent of potassium perchlorate in the original
sample.
p (total) = p(O2) + p(wc)
+ p(H2O)
734 mmHg = p(O2) + 1.64 mmHg
+ 19.8 mmHg
(since p(wc) = pressure
due to water column = height in millimetres divided by specific gravity
of Hg)
so p(O2) = 712.6 mmHg
Using PV=nRT, where P= 712.6
mmHg / 760 mmHg per atm, T = 295 K, R = 0.0206 L atm/K mol, and V = 0.0488
L we get that the moles of dioxygen, n= 1.89 X 10-3
Multiply by 2/3 to get the
moles of potassium perchlorate this came from, and then multiply by the
formula mass (138.547 g/mol) to get the mass of potassium perchlorate,
0.174 g.
Mass % = ( 0.174 g / 0.8988
g ) X 100% = 19.4 %
- [4] A compressed gas cylinder contains 1.00
x 103 grams of Ar and 8.20 x 102 grams of Ne.
The pressure inside the cylinder is 148.8 atm. The internal volume for
the cylinder is 17.8 L.
a)
Calculate the partial pressure for the Ar gas in the cylinder.
Using the atomic mass for
the monatomic gas, argon, 1000 g of Ar is 25.03 mol. Similarily there
are 40.63 mol of Ne in 820 g of the gas.
p(Ar) = (mole fraction of
Ar) * total pressure
= ( 25.03 mol / (25.03 mol
+ 40.63 mol) ) (148.8 atm) = 56.7 atm
b) What is the temperature of the gaseous mixture in
the cylinder?
T = PV / nR = (148.8 atm)(17.8
L) / [ (25.03 mol + 40.63 mol) (0.08206 L atm/K mol) ] = 492 K
- [3] Which of the following three p-block atoms,
P, S or Cl , has
a) the smallest first ionization energy?
S, because the fourth p-electron
is in a doubly occupied orbital, so it is repelled by the oother electron
in that orbital (phosphorus has three p-orbitals, all in singly occupied
orbitals)
b) the smallest radius?
Cl,
because it has the highest atomic number, or most protons, within the
period
c) the largest effective nuclear charge.
(Be sure to justify your answers)
Cl, for the same reason as above
- [3] Give the four quantum numbers for each electron in the valence
shell
of the N2+ ion.
N2+ : 2s22p1
so n=2 l=0 ml = 0 and ms = +/- 1/2
For the p electron there are several allowable
combinations. Here's one:
n=2 l=1 ml=-1
ms=+1/2
- [3] Which transition-metal tri-cation has the
electronic configuration [Xe]544f145d8
? How many electrons are left unpaired in this ion?
Au(III), 2 unpaired
- [6] Write down the complete electron
configurations for the following neutral atoms. Predict the three most
stable ions/oxidation states for each atom (apart from the zerovalent
state) and classify each ion/oxidation state according to its type.
Lastly, give the abbreviated electronic configuration for each ion/oxidation
state.
i) Selenium
|
inner |
valence |
type of config |
Se(0) |
1s22s22p63s23p6 |
4s23d104p4 |
|
Se(2-) |
1s22s22p63s23p6 |
4s23d104p6 |
noble gas |
Se(4+) |
1s22s22p63s23p6 |
4s23d10 |
inert pair |
Se(6+) |
1s22s22p63s23p6 |
3d10 |
pseudo noble gas |
ii) Antimony
|
inner |
valence |
type of config |
Sb(0) |
1s22s22p63s23p64s23d104p6 |
5s24d105p3 |
|
Sb(3-) |
1s22s22p63s23p64s23d104p6 |
5s24d105p6 |
noble gas |
Sb(3+) |
1s22s22p63s23p64s23d104p6 |
5s24d10 |
inert pair |
Se(5+) |
1s22s22p63s23p64s23d104p6 |
4d10 |
pseudo noble gas |
8. [13] Fill in each blank with the appropriate
answer.
i) Which element has the higher first ionization
energy: N or O? N
ii) The anion with the smallest radius is
F-
iii) The salt MnCl2 is _____________________
(diamagnetic/paramagnetic)
iv) The Tc3+ ion has
4 unpaired electrons in its
valence shell.
v) Apart from Group 2 metals and transition metals,
Group 14 (or 12) main-group metals can form
stable 2+ ions.
vi ) Hund’s rule states that the lowest energy
electron configuration for an atom is the
one that has the
maximum multiplicity, or number of unpaired electrons.
vii) As we go down a particular vertical group
in the periodic table, the effective
nuclear charge
stays approximately constant.
viii) What is the generalized valence shell electron
configuration common to all of the
halogens?
ns2np5
ix) Identify the neutral element that is isoelectronic
with the anion
As3- Kr
x)
Provide the appropriate value for the missing quantum number :
n = 3, l = 0, ml = _____?, ms
= -1/2. Zero! It's an s orbital
since l=0 so ther's no other choice.
xi) Max Planck found that energy can only be gained
or lost in whole number multiples of hv (read v
as the Greek 'nu')
xii) The n = 3 shell of the hydrogen atom contains
zero
f-orbitals.
xiii) Which of the following isoelectronic ions
has the largest radius?:
La3+,
I- or Te2-
9. [3] An unknown p-block element has the general
valence shell electron configuration
ns2np3.
a)
Would this element have a greater or smaller ionization energy
than fluorine?
smaller since, being in group 15
it's effective nuclear charge is less
b)
What is the formula of the compound this element would form with
Mg?
(represent the p-block element with the symbol A)
A3- + Mg2+
--> Mg3A2
c)
Would this element have a larger or smaller radius than Ba?
smaller - the biggest group 15
element is Bi, and it's smaller than Ba because it has a higher effective
nuclear charge
Bonus Question (2 marks):
A beam of electrons and a beam of protons are moving
with the same speed. Which has the longer de Broglie wavelength? Why?
Electrons are less massive than
protons, so electrons have a lower frequency. Lower frequency means longer
wavelength. The answer is electrons.
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