Practice term test #2
(NH2)2Se(s) --> 1/8Se8(s) + N2(g) + 2H2(g) A sample of solid diaminoselenium, (NH2)2Se(s), was placed in an evacuated cylinder and heated to 300 degrees C, resulting in the formation of a mixture of molecular nitrogen, elemental selenium and molecular hydrogen gas. After twenty minutes of heating at 300 degrees C, the reaction reached equilibrium and the total pressure climbed to a maximum value of 8.44 atmospheres. Some solid diaminoselenium was still present in the cylinder at equilibrium. Use the information given to calculate Kp for the diaminoselenium decomposition reaction at 300 degrees C. p(total) = 8.44 atm = p(N2) + p(H2) Let x = p(N2). Then, from the balanced reaction, since two moles of H2 form for every mole of N2 (which means that p(H2) = 2p(N2) ), it must be that i) p(N2) = x (already said this!) ii) p(H2) = 2x iii) since p(total) = p(H2) + p(N2), then p(total) = 3x p(total) = 8.44 atm = p(N2) + p(H2) = 3x x = 2.813 atm Kp =4 * (2.813)3 = 89.0
a) Write a balanced equation for the decomposition reaction. KClO4 (s) --> KClO (s) + 3/2 O2 (g) b) Calculate the mass percent of potassium perchlorate in the original sample. p (total) = p(O2) + p(wc) + p(H2O) 734 mmHg = p(O2) + 1.64 mmHg + 19.8 mmHg (since p(wc) = pressure due to water column = height in millimetres divided by specific gravity of Hg) so p(O2) = 712.6 mmHg Using PV=nRT, where P= 712.6 mmHg / 760 mmHg per atm, T = 295 K, R = 0.0206 L atm/K mol, and V = 0.0488 L we get that the moles of dioxygen, n= 1.89 X 10-3 Multiply by 2/3 to get the moles of potassium perchlorate this came from, and then multiply by the formula mass (138.547 g/mol) to get the mass of potassium perchlorate, 0.174 g. Mass % = ( 0.174 g / 0.8988 g ) X 100% = 19.4 %
a) Calculate the partial pressure for the Ar gas in the cylinder. Using the atomic mass for the monatomic gas, argon, 1000 g of Ar is 25.03 mol. Similarily there are 40.63 mol of Ne in 820 g of the gas. p(Ar) = (mole fraction of Ar) * total pressure = ( 25.03 mol / (25.03 mol + 40.63 mol) ) (148.8 atm) = 56.7 atm
b) What is the temperature of the gaseous mixture in the cylinder? T = PV / nR = (148.8 atm)(17.8 L) / [ (25.03 mol + 40.63 mol) (0.08206 L atm/K mol) ] = 492 K
a) the smallest first ionization energy? S, because the fourth p-electron is in a doubly occupied orbital, so it is repelled by the oother electron in that orbital (phosphorus has three p-orbitals, all in singly occupied orbitals) b) the smallest radius? Cl, because it has the highest atomic number, or most protons, within the period c) the largest effective nuclear charge. (Be sure to justify your answers) Cl, for the same reason as above
of the N2+ ion. N2+ : 2s22p1 so n=2 l=0 ml = 0 and ms = +/- 1/2 For the p electron there are several allowable combinations. Here's one: n=2 l=1 ml=-1 ms=+1/2
Au(III), 2 unpaired
i) Selenium
ii) Antimony
8. [13] Fill in each blank with the appropriate answer. i) Which element has the higher first ionization energy: N or O? N ii) The anion with the smallest radius is F- iii) The salt MnCl2 is _____________________ (diamagnetic/paramagnetic) iv) The Tc3+ ion has 4 unpaired electrons in its valence shell. v) Apart from Group 2 metals and transition metals, Group 14 (or 12) main-group metals can form stable 2+ ions. vi ) Hund’s rule states that the lowest energy electron configuration for an atom is the one that has the maximum multiplicity, or number of unpaired electrons. vii) As we go down a particular vertical group in the periodic table, the effective
nuclear charge stays approximately constant. viii) What is the generalized valence shell electron configuration common to all of the
halogens? ns2np5 ix) Identify the neutral element that is isoelectronic with the anion As3- Kr x) Provide the appropriate value for the missing quantum number : n = 3, l = 0, ml = _____?, ms = -1/2. Zero! It's an s orbital since l=0 so ther's no other choice.
xi) Max Planck found that energy can only be gained or lost in whole number multiples of hv (read v as the Greek 'nu') xii) The n = 3 shell of the hydrogen atom contains zero f-orbitals. xiii) Which of the following isoelectronic ions has the largest radius?: La3+, I- or Te2- 9. [3] An unknown p-block element has the general valence shell electron configuration ns2np3. a) Would this element have a greater or smaller ionization energy than fluorine? smaller since, being in group 15 it's effective nuclear charge is less b) What is the formula of the compound this element would form with Mg? (represent the p-block element with the symbol A) A3- + Mg2+ --> Mg3A2 c) Would this element have a larger or smaller radius than Ba? smaller - the biggest group 15 element is Bi, and it's smaller than Ba because it has a higher effective nuclear charge
Bonus Question (2 marks): A beam of electrons and a beam of protons are moving with the same speed. Which has the longer de Broglie wavelength? Why? Electrons are less massive than protons, so electrons have a lower frequency. Lower frequency means longer wavelength. The answer is electrons. |
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