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V-10
ANSWERS
MULTIPLE CHOICE
1.
b.
65.9%
2.
b.
2.66 x 10
-4
M
3.
b.
8.86 x 10
-4
M
4.
d.
CBr3COOH
5.
d)
NO3
-
will oxidize H2C2O
4
6.
a.
80.1 g mol
-1
7.
e.
initially orange then going colorless
8.
b.
-0.68V
9.
d.
0.000
10.
b.
-0.0197
11.
a.
be quadruple the original rate
12.
d.
3.0 x 10
4
J mol
-1
SHORT ANSWER
13.
i)
10.6 kJ
ii)
- 445 kJ mol
-1
iii)
3.76 kJ
iv)
-158 kJ mol
-1
. v)
-573 kJ mol
-1
14.
i)
Zn
2+
(aq)
+ 4 OH
-
(aq)
[Zn(OH)
4
]²
-
(aq)
ii)
[Zn
2+
] = 1.10 x 10
-22
M
iii)
1.50 x 10
17
15.
i)
1st order in S2O
8
2-
ii)
1st order in I
-
iii)
Rate =
[I2]/
t = k[I
-
]¹[S2O
8
2-
]¹
iv)
k = 0.0029 L mol
-1
s
-1
or 0.0029 M
-1
s
-1
